-3b^2-11b+70=0

Solution for -3b^2-11b+70=0 equation:

-3b^2-11b+70=0

a = -3; b = -11; c = +70;
Δ = b2-4ac
Δ = -112-4·(-3)·70
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-31}{2*-3}=\frac{-20}{-6}
=3+1/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+31}{2*-3}=\frac{42}{-6}
=-7
$